$\left(3ax-3x\right)\left(3a^2x+12ax^2+6ax^2\right)$
$5\left(5y-5\right)$
$3x^2+2x;\:x=0;\:x=-3$
$\frac{\infty^5}{5}$
$\left(-2-3\right)^2+4\cdot\left(-8\right)$
$\frac{4ax^2-ax+15-20x}{2xa-5};\:a=1$
$\frac{d}{dx}e^9$
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