$-4+-1+-1+-8$
$\left(2xy^2-3\right)\cdot dx+\left(2x^2y+4\right)\cdot dy=0$
$\frac{3x^3-2x^4-1-x^2}{x-2}$
$\frac{7}{2}+\frac{4}{2}+\frac{3}{2}+1$
$\frac{dy}{dx}=\frac{6x}{7y}$
$6x^2-2x-4$
$\ln\left(\sqrt{\frac{x^2}{x^6+1}}\right)$
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