$\frac{dx}{dt}=x+t$
$\lim_{x\to\infty}\left(\frac{x^2+5x+4}{x^2+4x+5}\right)$
$\frac{s^4-1296}{s+6}$
$\frac{x^2+x}{4x}$
$\frac{x^2-2\cdot x-15}{x^2-7\cdot x+10}$
$\left(8e+14f\right)^2$
$1+\left(x-2\right)\left(\frac{1}{3}x+\frac{5}{9}\right)$
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