$\left(6x^3+4ab^2\right)^2$

$2x^2-2x+2$

$\lim_{x\to\infty}\left(\frac{sin9x}{tan8x}\right)$

$\int3x^2\left(-1+x^3\right)dx$

$\lim_{x\to2}\left(10x^2-25x-15\right)$

$\lim_{x\to\infty}\left(-x\cdot\:cos\left(x\right)+sin\left(x\right)\right)$

$\frac{1}{2+2\cos\left(x\right)}=\frac{sin^2\frac{x}{2}}{sin^2x}$