$\frac{2x+1}{\left(x^2+1\right)\left(x-1\right)\left(x-3\right)}$
$5\:5x+6\:6x$
$2x\:x\:\tan\left(x\right)+3$
$2\sin\left(3x\right)=-1$
$9^4-16a^2b^2+36b^4$
$a^2+6a+9=0$
$\sqrt{1}3$
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