$x\left(4x^2+7\right)$
$\cos\left(2x\right)+\cos^2\left(x\right)=0$
$\left(\frac{d^2y}{dx^2}\right)-6=160x^3$
$x^2+4z^2-6x-y+10=0$
$-16\cdot7$
$\left(-8\right)\left(-5\right)+\left(-9\right)\left(2\right)-\left(\frac{-18}{9}\right)$
$\int\sqrt{t+1.63}dt$
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