$\left(\frac{2}{9}x^3y^2-\frac{4}{3}xy^3\right)^2$

$4\left(\infty^2\right)$

$\lim_{x\to0}\left(\frac{3x-sen\left(x\right)}{x^3}\right)$

$-\left(-3-5\right)-\left(-2-4\right)$

$x^8-\left(3yz\right)^4$

$x=\arcsin\left(1-y\right)$

$\lim_{x\to-2}\left(\frac{x^2+4x+3}{x^2+4x+5}\right)$