$\left(2x+3y\right)\left(2x+y\right)$
$5^3+3^4$
$5x-10>0$
$5\left(x-7\right)^2$
$\frac{216+w^3z^6}{6+wy^2}$
$\frac{dy}{dx}=\frac{3\left(2+y\right)}{\left(3-x\right)^{2}}$
$4y''-8y'+3y=0$
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