$3^{5x-y}=10$
$\int\left(4x^3-2x\right)\left(x^4-x^2-5\right)^5dx$
$6x^2-8+5a-3x-\left(x\left(6x-12\right)+4x-8\right)$
$\frac{\left(3\sqrt{x}-5\sqrt[3]{x^2}\right)}{2\sqrt[4]{x}}$
$\left(7-a\right)\cdot\left(7+a\right)$
$x^2+28x+81$
$11.8+8$
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