$\left(\frac{1}{9}+\frac{3}{b^{4}}\right)$
$\frac{x^2-2}{x^4-1}$
$0,\:7+0,\:3-1,\:3-0,\:7$
$3x+4x-7$
$\frac{16x^4y}{9x^8y^{-2}}$
$-4\left(3x+4\right)$
$2sin=-\sqrt{2}$
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