$3a^2b^3\:por\:-4x^2y$
$2x-1>3+x$
$3x^2-2x^2y+6x^2y+x^3$
$y'-4xy^2=0$
$\lim_{x\to0}\left(\frac{sin\left(2x\right)}{x\left(cos\left(x\right)\right)}\right)$
$\frac{x^3+0x^2-2x+4}{3x^2-1}$
$8sin\left(15z\right)cos\left(8z\right)$
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