$\frac{\cos\left(x\right)-\cos\left(3x\right)}{4\cos\left(x\right)}+\cos\left(x\right)^2=1$
$x^2+\frac{5}{3}x+1=0$
$3n^2+6n+3$
$2x-1^3$
$\frac{dy}{dx}=x\cdot e^{-x^3}-3\cdot x^2\cdot y$
$\frac{x^2+1}{x^2-1}$
$5\left(6-5\left(1\left(8-9\right)\right)\right)$
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