$\frac{dy}{dx}=\frac{2y-1}{5x+4}$
$\left(5-x^2\right)\left(25+5x^2+x^4\right)$
$-2x^2-x+3$
$\frac{t^4-8}{t^2}$
$4x^4-40x^2+36$
$e^{3x}dx=dy$
$\frac{d}{dx}\frac{e^{2x^2-5x}}{3x^2-2x}$
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