$2\left(x-3\right)=5x+0$
$\frac{0}{\omega}$
$\:-11-\left(-1\right)-\left(-1\right)+1=\:$
$x^2+14x+40$
$10a^2+29a+21$
$\frac{d}{dx}\left(x+7\right)^3\left(7x-2\right)^5$
$6\left(8x+3\right)=-22+8x$
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