$6^{x+3}=-1$
$\frac{3}{5}x-\frac{4}{5}\le\frac{3}{4}x-\frac{2}{3}$
$5x+6y-3x-8x+14y$
$x\:+\:6\:=\:-7x\:-\:2$
$\frac{3\sqrt{2-2\sqrt{3}}}{3\sqrt{2-2\sqrt{3}}}$
$x+1,\:9-x^2$
$x-6>21-8x$
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