$\frac{6x^2+3x}{3x}$
$\lim_{x\to\infty}\left(\frac{2x-4}{2x-1}\right)^x$
$\lim_{x\to\infty\:}\left(\frac{2x^2+3}{5x^3+6}\right)$
$sin^2x-cos^2x=2sin^2s-1$
$ln\left(1-x^2\right)$
$2x^2+8x+8>0$
$a\cdot a$
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