$\left(2\right)^3-6\left(3\right)^2+5$
$3-19+\left(-4\right)-\left(-8\right)+\left(-13\right)-\left(-12\right)+4-57$
$\frac{d}{dx}3^y$
$3x-5>10$
$\left(x^2-3y\right)^4$
$\int\frac{13x-8}{13x^2-16x+5}dx$
$4+5-3+5+6+2+3$
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