$16x^2+16xy+4y^2$
$\sqrt[4]{\frac{x+3}{x-1}}$
$\left(-2x+3\right).\left(x+2\right)-3x^2.\left(9x-5\right)$
$\int\sec^3\left(x\right)+\tan^3\left(x\right)dx$
$2cos2y=1$
$125-\left(-46\right)+\left(97\right)-\left(-201\right)$
$\left(1+y\right)^5$
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