$m-5m$
$\int\frac{x}{\left(x+1\right)\left(x+2\right)\left(2x+3\right)}dx$
$\int\frac{\tanh\left(x\right)}{1+\cosh\left(x\right)}dx$
$x^2-17x+5=0$
$\int x ^ { 2 } e ^ { x ^ { 3 } - 1 } d x$
$5x^3+2x^2-4x+6-2x^3-3x^2-6x+9$
$\frac{4x^2+6x}{-2x}$
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