$\frac{1}{1-\cos\left(x\right)}-\frac{1}{1+cos\left(x\right)}=2csc^2x$
$\frac{3x}{2}-1<-4$
$\sin\left(x\right)\left(\csc\left(x\right)-\sin\left(x\right)\right)=\sin^2\left(x\right)$
$5x+3=-27$
$4x^2-8x+4=y^2+3x+2$
$-\infty+3$
$x^2-\frac{8}{3}x+\frac{16}{9}^2$
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