$4x\left(3+\right)\left(-4\right)+6$
$\frac{2x^4-x^3+x^2-10}{x+3}$
$\frac{5}{2x-4}-\frac{2}{x+3}=\frac{3}{x-2}$
$9 ( 5 v - 3 ) + 4 ( 2 v + 5 )$
$a^2+b^2=15$
$\:\:\:\:\:\:\:\:log3\left(\frac{13w^2}{d}\right)$
$8+600p$
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