$\left(-\frac{1}{4}x+1\right)^2$
$cot^2x+4cscx=-5$
$\int\frac{2b+7}{\left(b^2+2b+5\right)}dx$
$-12\:x\:-8$
$a^2+4a+4^2$
$\lim_{x\to2}\frac{\left(x^2+x-6\right)}{x-2}$
$-7x^2\:-\:x\:+\:6x\:+\:x^2$
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