$-t\cdot8t^2$
$\ln\left(\frac{1+\tan\left(x\right)}{\tan\left(x\right)}\right)$
$8x-7=9$
$\lim_{x\to\infty}\left(\frac{12x-4x^2}{x^3-3x^2+4x}\right)$
$\frac{ax}{3-\sqrt{5a}}$
$\frac{y^6-x^4}{y^3-x^2}$
$6m^2-2m$
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