$\frac{10}{10^2}^8$
$\lim_{x\to\infty}\left(\ln\left(6x\right)-\ln\left(x+8\right)\right)$
$x^2-x-6\le0$
$\left(3m^2n^3w^5\right)^4$
$9\left(-3f+8\right)$
$\frac{dy}{dx}=\frac{y^2-1}{yx}$
$-\frac{27xy^2}{36yz}$
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