$\frac{-6x^5}{-3x^8}$
$cos4\theta\:-4cos2\theta\:=8sin^{\left(4\right)}\theta\:-3$
$-5+-y$
$\int\frac{4x}{\left(x+1\right)^3}dx$
$\frac{2}{\left(\left(s-1\right)^2+1\right)}$
$12n+15m-17n+2m$
$3n+7n+2n+x+8x$
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