$\int_0^5\left(900e^{-0.05x}\right)dx$
$x''+2x'+10x=0$
$\int_{x^2}^{\sqrt[3]{x}}7x\:dy$
$-\frac{-8}{-2}$
$-\left(2-5\right)+\left(3-7\right)+\left(-4\right)-\left(5-4\right)$
$\frac{dy}{dx}-8y\:=0$
$-6\left(2x-\frac{1}{3}\right)$
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