$\frac{u^2-3u}{7}=0$
$\lim_{x\to\infty}\left(15+4x\right)$
$-\left(-2n^5x^5d^3\right)^3$
$2.2^2$
$\left(10y^4\:-\:5y^3\right)^2$
$\int\left(x^3-\left(x^3-12x\right)\right)dx$
$\int\left(x\left(x+6\right)^5\right)dx$
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