$2x^2+8x+8$
$\int\frac{\left(\sqrt{x^2+4}\right)}{y}dx$
$p^2\:-\:\frac{5}{2}p\:+\:1\:=0$
$\frac{1-\sin^2x}{cosx}=\cos x$
$\:-2x+10=2\:\left(x-5\right)$
$\int\tan^43xdx$
$\int\frac{x^2}{x^3+8}\:dx$
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