$x^2+10x+12=0$
$\int\left(x-3\right)\cos x\left(x-3\right)dx$
$\left(\frac{3}{2}x+3y\right)^3$
$+4\cdot\left(-3\right)\cdot\left(+6\right)$
$integral\left(2x+3\right)\cdot\sqrt[3]{x-1}$
$2-4x<-8-2x$
$\frac{q^2}{q^6}$
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