$x^2+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$
$\lim_{x\to\infty}\left(1+2x\right)^{\frac{1}{\sin\left(x\right)}}$
$\left(3a^3-a^2\right)$
$\frac{10m^{-2}n}{15mn^{-3}}$
$x^2-7x-49$
$-5\left[-72\right]\:+16$
$\int x^3\cdot e^{4x-5}dx$
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