$\frac{1}{6-x},\:c=1$
$3x^3+13x^2-13x+2\:3x-2$
$dx-e^{2x}dy=0$
$\left(8x^2y+9m^3\right)^3$
$\log\left(10x^3\right)$
$\int\:\:x\left(1-3x^2\right)dx$
$\frac{dy}{dx}=\frac{\left(lnx\right)^4}{xy^2}$
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