$8r\:+\:32\:=\:88$
$12^{-3}\:.\:12^9$
$3x=-15$
$\int\frac{\left(100x\right)}{\left(x+10\right)}dx$
$-9\cdot\left(-7\right)\cdot5$
$cos\:15=\frac{\sqrt{a}\left(\sqrt{b}+1\right)}{4}$
$\int\:\left(x^2-3\right)^3\:8x\:dx$
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