$10x^3+8x+12$
$113,9-43,7$
$3x\left(x-2\right)-5\left(4x-2x^2\right)$
$\left(4x^2-10x\right)-\left(3x^2+6x-32\right)$
$\frac{4^7}{4^3}$
$\left(\left(-16\right)+\left(-2\right)\right)-\left(-17\right)$
$\frac{4x^5-3x^2+x-+1}{1-2x^3}$
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