$\lim_{x\to4}\left(\frac{1}{\left(x-4\right)^2}\right)$
$\sin\left(1.4\right)$
$\int\frac{x^2}{\left(4-x^3\right)^2}dx$
$-3-\left(4+5\right)-\left(3-5\right)$
$\int\frac{\:4x+26}{x^2+8x+15}dx$
$4-2a+4a+5-7-3a$
$\frac{dx}{db}=6-y-2x$
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