$y^2=x^2$
$\lim_{x\to5}\left(\frac{3}{x-5}\right)$
$\frac{1}{3}\log\left(x\right)$
$\frac{2x-4}{4}\ge\frac{3x+2}{5}$
$6x^2+33x+15$
$10\:+\:4t\:-\:6y$
$-x^2+2x+3>0$
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