$r^2-12r+41=0$
$\lim_{x\to0}\left(\frac{e^x-1}{3x+1}\right)$
$0.0013717421124828531\:x\:4$
$6c^2-23c-4$
$\lim_{x\to0}\left(-4+5n\right)^2$
$\lim_{x\to2}\left(5x+3\sqrt{29-2x}\right)$
$7x\:+\:28\:\cdot\:5$
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