$\left(x^2+3x+2\right)entre\:\left(x+1\right)_:^{\circ}$
$10^{m-5}\cdot10^{2m+5}$
$3x-5x+x=10$
$3x^2-30x+0$
$\frac{dy}{dx}=\frac{\left(y-1\right)}{x+3}$
$3+2\cdot\left(4-5\right)+2\cdot3$
$\sen^{2}\theta-\cos^{2}\theta=1-2\cos^{2}\theta$
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