$\frac{3x^2+2}{x+3}$
$-\frac{3w}{4}<-9$
$7x+9=6x-5$
$7b\:-\:b\:=\:0$
$16-\left(1+x\right)^2$
$\lim_{x\to0}\left(\frac{2}{2^x-2^{-x}}\right)$
$\left(-7x^4+6x^2+6x+5\right)-\left(3x^5-2x^2+2\right)$
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