$3.77\cdot2.125$
$-9x+2\ge11$
$\frac{x-3}{x^2-3x}$
$6-2x\le x+3$
$-2x^2-6x+36$
$\int\frac{x^2}{\left(3-x^2\right)^{\frac{5}{2}}}dx$
$\left(x-2\right)\left(x^4-9x+8\right)$
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