$\left(x^3+12\right)\left(x^2+12\right)\left(x+48\right)$
$\int\left(\ln\left(3x+1\right)^3\right)dx$
$\int5ay^2dy$
$\frac{d^2u}{dxdy}+u=0$
$\left(8x^3+5x^2-3x-6\right)-\left(-4x^3+7x^2+2x-8\right)$
$\sqrt[3]{125\cdot27}$
$\frac{m^3-343b^6}{m-7b^b}$
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