$\log_{27}x=\frac{1}{3}$
$\frac{x-2}{3}<5$
$18-\left(-15\right)-6-5+10$
$2x-7\ge5$
$\log\left(4x-2\right)=\log\left(-5x-5\right)$
$x^2+16x-48$
$-\left|-13+\left(24-68\right)\right|-\left(-48+95\right)$
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