$-\left(x+5\right)=-x-5$
$\left(e^{\cdot}+1\right)^2$
$9a+\frac{7}{9}<0$
$2x+7,\:x=-3$
$2x+1=-x+4$
$\int9\left(6x-5\right)^{\frac{4}{7}}dx$
$\left(3m^2n+2n\right)^2$
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