$\left(36^{3\:}:\:6^3\right)\::\:6^2$
$4x+4\ge x$
$5x^3\:-\:6x^2y\:+\:7xy^2+\:6y^3\left(5x\:+\:4y\right)$
$2y'=y^3coa$
$+3x-4x-2$
$34j^2+92j=0$
$\lim_{x\to2}\left(-\frac{\sqrt{4-x^2}}{x-2}\right)$
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