$\frac{dy}{dt}=\frac{y^2}{t}$
$\int\frac{3x^2}{x^2+8}dx$
$\left(\frac{3}{8}x^2+\frac{1}{4}x-\frac{2}{5}\right)\:por\:2x^3-\frac{1}{3}x+2$
$\sqrt{\left(6xy\right)\left(4xy^3\right)}$
$\frac{x^3+2x-1}{x+3}$
$xy\:.\:x^2$
$2x\:+\:5\:=\:2x\:-\:5$
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