$\left(62.4\:\right)\int_0^4\left(10-x\right)\:\left(\sqrt{16-x^2}\right)dx$
$\int\frac{1}{\left(x^2+5\right)^3}dx$
$12x^2-4x$
$\left(\frac{\left(a^{x^2}+y^2\right)^2}{\left(a^{x^2}+y^2\right)^3}\right)$
$\int\frac{60x^4}{4x^5-5}dx$
$28=9x-8$
$\left(8m-3\right)^2$
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