$x^2+4x\cdot5$
$-4\cdot8\left(-2\right)$
$2\left(-16+8z\right)=-48$
$-2-18-\left(-22\right)+\left(-4\right)$
$99\cdot99$
$\left(2c-3d\right)^5$
$x^2-x+112=0$
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