$\frac{\left(x^3+10\right)}{\left(x^2+5x+6\right)}$

$-\left|12+\left(-3\right)\right|-\left(-4\right)-5+6-\left(-4\right)$

$-9+3x-12-4x$

$sin\left(2x\right)-2sin\left(x\right)+1=0$

$213+0.45$

$64x^2+4x^2z+\frac{z^2}{16}$

$\frac{\cos\left(x\right)-\cos\left(3x\right)}{\sin\left(3x\right)-\sin\left(x\right)}=\tan2x$