$\ln\sqrt{x+1}=1$
$\left(5-2i\right)^{2}$
$\int_0^4\sqrt{1+\left(4-2x\right)^2}dx$
$\sec\left(a\right)-\tan\left(a\right)\sec\left(a\right)+\tan\left(a\right)=1$
$\left(a^8+16\right)^4$
$2x+6<3x-1$
$\int\frac{\ln\left(17x\right)}{5x}dx$
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