$15\le x+2$
$\frac{8x^2+4x-7}{x^2+1}$
$a^2-2a=15$
$t^2\frac{dy}{dt}-t=1+y+ty,\:y\left(1\right)=6$
$\int3\:\tan\left(3x\right)dx$
$-1.8log\left(\frac{0.01^{1.11}}{3.7^{1.11}}+\frac{6.9}{x}\right)$
$x^2-8x-15=-x^2$
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