$\left(2x-3z^2\right)^5$

$\left(+12\right)-\left(-3\right)-\left(+2\right)+\left(4\right)$

$\int\left(x^{\frac{3}{5}}+x^5-2x^{\frac{1}{3}}+x+1\right)dx$

$\left[4a^2+4b^2\:\right]^2$

$\left(3a^y+\frac{1}{2}a^{3x}b^{4y}\right)^2$

$\frac{\left(2\right)}{\left(2-c\right)}>-4$

$6x^2+7x-10=0$