$\frac{h^2+2xh}{h}$
$8\left(2x-3y\right)+4\left(y-3x\right)$
$\frac{dy}{dx}=\frac{5x}{1+2y}$
$\sqrt{\frac{4x-3}{2x+7}}$
$8x^2-16x+16$
$\frac{dy}{dx}\left(x^2-x\right)-y=0$
$\left(-8\right)-\left(-5\right)\cdot\left(+4\right)+\left(+7\right)\cdot\left(-2\right)$
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